In Swift, if you encounter a “Result of call to ‘function’ is unused” warning, it means that you’re calling a function that returns a value (typically a result type, such as Result
or any other type), but you’re not doing anything with the result. To get rid of this warning, you have a few options depending on the specific situation:
-
Use the Result Value: If the function returns a result, it’s usually important to handle the result appropriately. You should evaluate the result and take action based on whether it’s a success or a failure. You can use a
switch
statement orif
conditions to handle the result:let result = someFunctionThatReturnsAResult() switch result { case .success(let value): // Handle the success case print("Success: \(value)") case .failure(let error): // Handle the failure case print("Error: \(error)") }
-
Discard the Result: If you’re intentionally ignoring the result (for example, if you’re calling a function solely for its side effects and don’t care about the result), you can use an underscore (
_
) to explicitly indicate that you’re intentionally discarding the result:_ = someFunctionThatReturnsAResult()
Using
_
tells the Swift compiler that you’re aware of the result but don’t need to use it. -
Suppress the Warning: If you have a specific reason to suppress the warning for a particular line of code (though this is generally not recommended), you can use the
@discardableResult
attribute:@discardableResult func someFunctionThatReturnsAResult() -> ResultType { // Function implementation }
Adding
@discardableResult
indicates that callers are allowed to discard the result without triggering a warning.
It’s important to choose the option that best aligns with the intended behavior of your code. In most cases, you should handle the result or at least acknowledge that you’re intentionally discarding it to make your code more readable and maintainable.